Question

the product of two rational numbers is -2by3 If one of them is 16by39 find the other​

Answer 1

Given:-

• Product of two rational number is $\dfrac{-2}{3}$
• One number is $\dfrac{16}{39}$

To find:

• Another number?

Solution:

Given that product of two numbers are $\dfrac{-2}{3}$ in which one number is $\dfrac{16}{39}$.

• Let suppose that another (required) number is x

Therefore,

$\dfrac{16}{39}×x\:=\:\dfrac{-2}{3}$

$\implies\dfrac{16x}{39}\:=\:\dfrac{-2}{3}$

$\implies{16x\:=\:\dfrac{-2}{3}×39}$

$\implies{16x\:=\:\dfrac{-78}{3}}$

$\implies{16x\:=\:-26}$

$\implies{x\:=\:\dfrac{-26}{16}}$

$\implies{x\:=\:\dfrac{-13}{8}}$

Therefore,

• Value of another number is $\dfrac{-13}{8}$

Answer 2

Answer:

Step-by-step explanation:

Let the other number be x

$x\times \left ( -\frac{2}{3} \right )=\frac{16}{39}\\\\\Rightarrow x=\frac{16}{39}\div \left ( -\frac{2}{3} \right )\\\\\Rightarrow x=\frac{16}{39}\times \frac{-3}{2}\\\\\Rightarrow x=\frac{-8}{13}$

So, the other number will be $-\frac{8}{13}$