Question

The product of two rational numbers is 7/9. If one of the number is 12/49 , find the other number

Answer 1

Let the other number be A

12/49 × A = 7/9

A = 7/9 × 49/12

A = 343/108

Hence, the other required number is 343/108

Answer 2

Answer:

$\huge{\red{\boxed{\boxed{\green{\sf{x=\frac{343}{108}}}}}}}$

Step-by-step explanation:

$\huge{\red{\boxed{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}}$

□Let unknown number be x

○According to the question:

$\frac{12}{49} \times x = \frac{7}{9} \\ = ) \frac{12 \times x }{49} = \frac{7}{9} \\ = ) \frac{12x}{49} = \frac{7}{9} \\ cross \: multiply \: the \: fraction \\ = ) 12x \times 9 = 7 \times 49 \\ = )12x = \frac{7 \times 49}{9} \\ = )12x = \frac{343}{9} \\ = )x = \frac{343}{9 \times 12} \\ = )x = \frac{343}{108}$

☆So required number:

$\huge{\red{\boxed{\boxed{\green{\sf{x=\frac{343}{108}}}}}}}$

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