Question

the product of two rationalnumber is 15/56 if one of the number is _5/48 find the other
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Answer 1

Given

$\bold{Product \ of \ two \ rational \ numbers} = \dfrac{15}{56}$

$\bold{One \ of \ the \ rational \ number} = \dfrac{5}{48}$

Let the other number be x.

$\implies \dfrac{5}{48} x = \dfrac{15}{56}$

$\implies x = \dfrac{15}{56} \times \dfrac{48}{5}$

$\implies x = \dfrac{3}{56} \times 48$

$\implies x = \dfrac{3}{14} \times 12$

$\implies x = \dfrac{3}{7} \times 6$

$\implies x = \dfrac{18}{7}$

$\boxed{\boxed{\bold{Therefore, \ the \ other \ number \ is \ \frac{18}{7}}}}}}}$

                                                               

Answer 2

AnsWer :

18 / 7.

To FinD :

Th value of Other number.

SolutioN :

Let,

• The other number be x.

# Condition :

• The product of two rational number is 15/56.
• One of them is 5 / 18.

$\tt \dagger \: \: \: \: \: \dfrac{5}{48} \times x = \dfrac{15}{56}$

Let find the value of x.

$\tt : \implies \dfrac{5}{48} \times x = \dfrac{15}{56}$

$\tt \longmapsto x = \dfrac{15}{56} \times \dfrac{48}{5}$

$\tt \longmapsto x = \dfrac{ \cancel{15}}{56} \times \dfrac{48}{ \cancel5}$

$\tt \longmapsto x = \dfrac{3}{ \cancel{56}} \times \dfrac{ \cancel{48}}{1}$

$\tt \longmapsto x = \dfrac{3}{28} \times \dfrac{24}{1}$

$\tt \longmapsto x = \dfrac{3}{14} \times \dfrac{12}{1}$

$\tt \longmapsto x = \dfrac{\cancel{36}}{\cancel{14}}$

$\tt \longmapsto x = \dfrac{18}{7}$

Therefore, the value of Other number is 18 / 7.

$\rule{200}3$

VerificatioN :

→ 5 / 48 * 18 / 7 = 15 / 56.

→ 90 / 336 = 15 / 56.

→ 30 / 112 = 15 / 56.

→ 15 / 56 = 15 / 56.

★ Hence Verify.