the product of two successive integral multiples of 5 is 300 determine the multiples
Answers
Answered by
3
let be successive no. are x and x+1 .
5x( 5x+1 ) = 300
25x^2 + 5x - 300 = 0
5(5x^2 + x -60) = 0
5x^2 + x - 60 = 0
5x( 5x+1 ) = 300
25x^2 + 5x - 300 = 0
5(5x^2 + x -60) = 0
5x^2 + x - 60 = 0
Answered by
8
Hey,
Thanks for asking this question.
Lets suppose that first multiple = P
So second successive integral multiple of 5 is P+5.
But according to question,
P × (P+5) = 300
=> P×P + 5P = 300
=> P×P + 5P - 300 = 0
=> P×P + 20P - 15P -300 = 0
=> (P+20) (P-15) = 0
=> P = -20 OR P= 15.
•IF ONE MULTIPLE IS -20, THEN OTHER MULTIPLE IS -15.
•IF ONE MULTIPLE IS 15, THEN OTHER MULTIPLE IS 20.
●Hope my answer helped
Thanks for asking this question.
Lets suppose that first multiple = P
So second successive integral multiple of 5 is P+5.
But according to question,
P × (P+5) = 300
=> P×P + 5P = 300
=> P×P + 5P - 300 = 0
=> P×P + 20P - 15P -300 = 0
=> (P+20) (P-15) = 0
=> P = -20 OR P= 15.
•IF ONE MULTIPLE IS -20, THEN OTHER MULTIPLE IS -15.
•IF ONE MULTIPLE IS 15, THEN OTHER MULTIPLE IS 20.
●Hope my answer helped
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