the product of two successive multiple of 100 and 1200
Answers
HELLO DEAR,
GIVEN :- The product of two successive
multiple of 100 and 1200.
SOLUTION:- The two successive multiple of 100 is
100× 2 = 200
and 100× 3 = 300
So, there product is,
200× 300 = 60000.
The two successive multiple of 1200 is,.
1200×2 = 2400
1200×3 = 3600
So, there product is,
2400× 3600 = 8640000.
OR
IF THE QUESTIONS IS:-
GIVEN:- The product of two successive multiples of 10 is 1200. Then find these multiples:
SOLUTION- Let the first multiple of 10 is x.
And its successive multiple of x is (x+10).
Then as per question ,
x × ( x+ 10) = 1200
x^2 + 10x = 1200
x^2 + 10x - 1200 = 0
x^2 + 40x - 30x - 1200 = 0
x ( x + 40 ) -30 ( x + 40) = 0
(x - 30) ( x + 40 ) = 0
x = 30 , x = -40.
Therefore ,
X= 30 & - 40
if,x= 30 , then numbers are 30,40
if x = -40 , then numbers are-40,-30
I HOPE IT'S HELP YOU DEAR,
THANKS
Correct Question :- The product of two successive multiples of 10 is 1200 . Then find these multiples ?
Solution :-
Let us assume that, first multiple of 10 is 10x and next multiple of 10 is 10y .
then,
→ First multiple * next multiple = 1200
→ 10x * 10y = 1200
→ 100xy = 1200
dividing both sides by 100,
→ xy = 12
Now,
- if x = 1, y = 12 => both are not consecutive numbers .
- if x = 2, y = 6 => both are not consecutive numbers .
- if x = 3, y = 4 => both are consecutive numbers .
Therefore,
→ First Multiple = 10x = 10 * 3 = 30
→ Next Multiple = 10y = 10 * 4 = 40 .
Hence, Required multiples are 30 and 40 respectively .
Note :-
As we know , if we multiply two negative numbers we get a positive number, since in question natural number is not mentioned , we can conclude that, given two successive multiples of 10 can be negative numbers also , which are (-30) and (-40) .
As,
- (-30) * (-40) = 1200 .
Therefore, Required multiples are also (-30) and (-40) respectively .
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