Question

The product of two successive multiples of 10 is 1200. then find these multiples​

Answer 1

Answer:

the multiples are 30 and 40

Step-by-step explanation:

let the two successive multiples be X and (X +10)

therefore the equation becomes-

x ( X+10)= 1200

= x² + 10x- 1200=0

Now applying quadratic formula,

we get X=30

The solution can be seen in the attached photo

Hope it helps

Answer 2

Given:

The product of two successive multiples of 10 is 1200.

To find:

The successive multiples.

Solution:

Let the first multiple of 10 is x.

Its successive multiple is x+10

According to the question:

=> x (x+10) = 1200

=> x²+10x-1200 = 0

=> x²-30x+40x-1200 = 0

=> x(x-30)+40(x-30) = 0

=> (x+40)(x-30) = 0

=> x+40=0 or x-30=0

=> x+40=0

=> x = -40

Here, the multiples are -40 and -30

=> x-30=0

=> x=30

Here, the multiples are 30 and 40

Hence, two successive multiples are 30 and 40 or -40 and -30

Verify :

The product of two successive multiples of 10 is 1200.

=> 30 x 40 = 1200

or

=> -40 x -30 = 1200.