Question

the product of two successive multiples of 10 is 1200. then find these multiples
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Answer 1

Answer:

30 and 40

Let the first multiple be x.

Next multiple = x+10

According to Question,

x (x+10) = 1200

=> x²+10x-1200 = 0

=> x²-30x+40x-1200 = 0

=> x(x-30)+40(x-30) = 0

=> (x+40)(x-30) = 0

=> x = 30 or x = -40

Neglecting negative value of x.

The multiples are 30 and 40.