Question

The product of two successive multiples of 10 is 1200. Then find these multiples:10 के 2 लगातार गुणजों The product of two successive multiples of 10 is 1200. Then find these multiples:10 के 2 लगातार गुणजों The product of two successive multiples of 10 is 1200. Then find these multiples:10 के 2 लगातार गुणजों ​

Answer 1

Step-by-step explanation:

let the consecutive integers be x,x+1

multiples of 10

so,

10(x) , 10(x+1)

10x, 10x + 10

(10x) (10x+10) = 1200 [ from the question ]

100x2 + 100x - 1200 = 0

x2+x - 12 = 0 [ taking 100 as common]

by factorisation method,

x2 + 4x - 3x -12

x( x + 4) -3( x+4)

x= -4 or 3

taking x = 3

10x = 10 x 3

= 30

10x + 10 = 30+10 = 40