the product of two successive multiples of 10 is 1200then find these multiples
Answers
Answered by
2
Answer:
30 and 40
Step-by-step explanation:
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Answered by
0
Answer:
Let the number be
First No. = 10x
Second No. = 10x + 10
According to question -:
First No. × Second No. = 1200
10x × 10x+10 = 1200
100x^2 + 100x = 1200
100x^2 + 100x - 1200 = 0
Now Factorize using Middle term splitting -:
100(x^2 + x - 12) = 0
x^2 + x - 12 = 0
x^2 + 4x - 3x - 12 = 0
x (x+4) -3 (x+4) = 0
(x+4) (x-3) = 0
x = 3
x = -4
We will take x = 3. Now -:
First No. = 10x
= 10×3
= 30
Second No. = 10x+10
= 10×3 + 10
= 30 + 10
= 40
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