Question

the product of two successive multiples of 10 is200 then find these multiples option (1)20,30(2)48,25(3)60,20(4)30,40​

Answer 1

Answer:

(4)

Step-by-step explanation:

no explanation needed

Answer 2

$\underline{\textsf{\textbf{\pink{ \mapsto Given:}}}}$

• The product of two succesive multiples of 10 is 1200.

$\underline{\textsf{\textbf{\purple{ \mapsto To\:Find:}}}}$

• The two numbers.

$\underline{\textsf{\textbf{\pink{ \mapsto Concept\:Used:}}}}$

• The number is a multiple of 10 , so it will be divisible by 10 . So it will be in the form of 10k , where k is any integer . So if the first number will be 10k , then the second number will be 10k + 10 since they are succesive numbers.

$\underline{\textsf{\textbf{\purple{ \mapsto Answer:}}}}$

$\sf Let \:us\:take:-$

$\sf \green{Firsrt\: number\:be\:10x.}$

$\sf \red{Second\: number\:be\:10x+10.}$

$\underline{\underline{\purple{\longmapsto \sf So,\: \mathscr{A}ccording \:to\: the\; \mathscr{Q}uestion ,}}}$

$\large\bf{\pink{\tt:\implies 10x(10x+10)=1200} }$

$\large\bf{\purple{\tt:\implies 100x^2+100x=1200} }$

$\large\bf{\pink{\tt:\implies 100x^2+100x-1200=0} }$

$\large\bf{\purple{\tt:\implies 100(x^2+x-12)=0} }$

$\large\bf{\pink{\tt:\implies x^2+x-12=\dfrac{0}{100}} }$

$\large\bf{\red{\tt:\implies x^2+x-12=0} }$

$\large\bf{\green{\tt:\implies x^2+4x-3x-12=0} }$

$\large\bf{\red{\tt:\implies x(x+4)-3(x+4)=0} }$

$\large\bf{\green{\tt:\implies(x+4)(x-3)=0} }$

$\underline{\underline{\boxed{\pink{\tt\longmapsto x=(-4),3}}}}$

$\bf Hence\: values\:of\:x\:is\:(-4)\:\&\:3$

$\underline{\pink{\purple{\mapsto}\tt\:When\:x\:is\:(-4).}}$

$\sf First\: Number\:=\:10x\:=\orange{(-40)}$

$\sf Second\: Number\:=\:10x+10\:=\orange{(-30)}$

$\underline{\pink{\purple{\mapsto}\tt\:When\:x\:is\:(3).}}$

$\sf First\: Number\:=\:10x\:=\orange{(30)}$

$\sf Second\: Number\:=\:10x+10\:=\orange{(40)}$