Question

the product of two successive multiples of 10is 1200 .Then find these multiples ​

Answer 1

Given :

The product of two successive multiples of 10 is 1200.

To find :

Multiples of 10

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Step by step explanation:

Let the first multiple of 10 be 10x

second multiple of 10 be 10x+10

According to the question:-

$= > 10x(10x + 10) = 1200$

$= > 100 {x}^{2} + 100x = 1200$

$= > 100 {x}^{2} + 100x - 1200 = 0$

Dividing equation by 100,we get

$= > {x}^{2} + x - 12 = 0$

$= > {x}^{2} + 4x - 3x - 12 = 0$

$= > x(x + 4) - 3(x + 4) = 0$

$= > (x - 3)(x + 4) = 0$

X=3 and x=-4

we take positive value:-

First multiple =10x=10×3=30

second multiple =10x+10=30+10=40

Therefore ,the two successive multiples are (30,40)

Check it's product is 1200

40×30=1200