Math, asked by sheetalbawa3, 7 months ago

the product of two successive multiples of 5 is 300.what are the values of these multiples

A natural number when increased by 12 equals to 160 times of its reciprocal find the number

If the arthmetic mean of 5,4,×,×+3,9 and 8,is 6,find out value of x ​

Answers

Answered by rosmigeorge239
0

Answer:

answer1

let 5n & 5(n+1) be the successive multiples of 5

product, 5n x 5(n+1) = 300

5n *(5n+5) = 300

(25n^2)+ 25n =300

n^2+n=12 (÷by25)

solving the Quadratic equation we get

n=3, n=(-4)

go for the positive value always, so n is 3

now substitute in 5n and 5(n+1)

5n=15 & 5(n+1) =20

15*20=300

answer2

natural number(want to find ie 'n') increased by 12=(n+12)

160 times of its (n) reciprocal= 160/(n)

they are equal,

n+12 = 160/(n)

n(n+12) =160 cross multiplying

n^2+12n=160

solving the quadratic equation

n=20, n=(-8)

go for the positive, so n is 20

answer3

arithemetic mean of given numbers, the sum of the numbers divided by the total number of the given numbers, here there are 6 numbers,

{5+4+x+(x+3) +9+8}/6=6

{26+x+(x+3) }/6 =6

{26+x+x+3}/6 =6

{29+2*x}/6 =6

{29+2*x}= 6*6

{29+2*x}=36

{2*x}=36-29

{2*x}=7

{x}=7/2

x =3.5

Step-by-step explanation:

kindly inform if this helps........

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