the product of two successive multiples of 5 is 300.what are the values of these multiples
A natural number when increased by 12 equals to 160 times of its reciprocal find the number
If the arthmetic mean of 5,4,×,×+3,9 and 8,is 6,find out value of x
Answers
Answer:
answer1
let 5n & 5(n+1) be the successive multiples of 5
product, 5n x 5(n+1) = 300
5n *(5n+5) = 300
(25n^2)+ 25n =300
n^2+n=12 (÷by25)
solving the Quadratic equation we get
n=3, n=(-4)
go for the positive value always, so n is 3
now substitute in 5n and 5(n+1)
5n=15 & 5(n+1) =20
15*20=300
answer2
natural number(want to find ie 'n') increased by 12=(n+12)
160 times of its (n) reciprocal= 160/(n)
they are equal,
n+12 = 160/(n)
n(n+12) =160 cross multiplying
n^2+12n=160
solving the quadratic equation
n=20, n=(-8)
go for the positive, so n is 20
answer3
arithemetic mean of given numbers, the sum of the numbers divided by the total number of the given numbers, here there are 6 numbers,
{5+4+x+(x+3) +9+8}/6=6
{26+x+(x+3) }/6 =6
{26+x+x+3}/6 =6
{29+2*x}/6 =6
{29+2*x}= 6*6
{29+2*x}=36
{2*x}=36-29
{2*x}=7
{x}=7/2
x =3.5
Step-by-step explanation:
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