Question

The product of two successive multiples of 5 is 300. What are the values of these multiples? 5​

Answer 1

Given,

The main numbers are two successive multiples of 5.

Product of these multiples is 300.

To find,

The value of those multiples.

Solution,

Let, the first multiple = x

So, the second multiple will be = x+5

(Because, they are successive multiples of 5, so the common difference between them will be 5.)

According to the data mentioned in the question,

x × (x+5) = 300

x²+5x = 300

x²+5x-300 = 0

(x-15) (x+20) = 0 (Splitting "b" is such two parts that the multiplication of those two parts will produce the exact numerical value of "c", ie. b = 5 = 20-15 >> (-15×20) = -300)

So,

x-15 = 0

x = 15

And,

x+20 = 0

x = -20

For, the 15 as the value of x

The first multiple = 15

The second multiple = 15+5 = 20

For, the -20 as the value of x

The first multiple = -20

The second multiple = -20+5 = -15

Hence, the multiples are 15 and 20 or -15 and -20.

Answer 2

SOLUTION :

GIVEN

The product of two successive multiples of 5 is 300

TO DETERMINE

The values of these multiples

CALCULATION

Let the two multiple of 5 be x and x + 5

Then by the given condition

$\sf{}x(x + 5) = 300$

$\implies \sf{} {x}^{2} + 5x - 300 = 0$

$\implies \sf{} {x}^{2} + 20x -15x - 300 = 0$

$\implies \sf{}x(x + 20) - 15(x + 20)= 0$

$\implies \sf{}(x + 20) (x - 15)= 0$

Which gives

$\implies \sf{}either \: (x + 20) = 0 \: \: \: or \: \: \: (x - 15)= 0$

$\sf{}Now \: x + 20 = 0 \: \: gives \: \: x = - 20$

In this case the multiples are - 20 & - 15

$\sf{}Again \: \: x - 15 = 0 \: \: gives \: \: x = 15$

In this case the multiples are 15 & 20

FINAL ANSWER

Hence the required multiples are - 20, - 15 or 15, 20

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LEARN MORE FROM BRAINLY

Let r be a positive number satisfying

r^(1/1234) + r^(-1/1234) = 2

then find (r^4321)+(r^-4321)

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