Question

the product of two successive multiples of 5 is 300 what are the values of these multiples ?

Answer 1

Step-by-step explanation:

Assume the consecutive integral multiple of 5 be 5n and 5(n + 1) where n is a positive integer.

ATQ

5n x 5(n + 1) = 300

n2 + n – 12 = 0

(n – 3) (n + 4) = 0

n = 3 and n = – 4.

As n is a positive integer so n =3.

Hence the required numbers are 15 and 20.

Answer 2

Step-by-step explanation:

let's take 2 successive multiples of 5 as 5n and 5(n+1)

the product of these unknown multiples,

5n*5(n+1)=300

5n*(5n+5)=300

(25n^2)+25n-300=0

(n^2) +n-12=0 (÷by25)

by solving the quadratic equation, we get

n=3,orn=(-4)

let's go for the positive....so the actual n value is 3

now substitute the n value in 5n & 5(n+1) ,

5n=5*3=15

5(n+1)=5(3+1)=5*4=20

let's check

15*20=300....