the product of two successive multiplies of 5 is 300. determine the multiples.
Answers
Answered by
8
Hi ,
Let a , ( a + 5 ) are two successive multiples
of 5 .
according to the problem given ,
product these numbers = 300
a( a + 5 ) = 300
a² + 5a - 300 = 0
a² + 20a - 15a - 300 = 0
a( a + 20 ) - 15( a + 20 ) = 0
( a + 20 )( a - 15 ) = 0
a + 20 = 0 or a - 15 = 0
a = -20 or a = 15
Now ,
Required two numbers are
1 ) If a = -20 ,
a + 5 = -20 + 5 = -15
2 )If a = 15 ,
a + 5 = 15 + 5 = 20
I hope this helps you.
: )
Let a , ( a + 5 ) are two successive multiples
of 5 .
according to the problem given ,
product these numbers = 300
a( a + 5 ) = 300
a² + 5a - 300 = 0
a² + 20a - 15a - 300 = 0
a( a + 20 ) - 15( a + 20 ) = 0
( a + 20 )( a - 15 ) = 0
a + 20 = 0 or a - 15 = 0
a = -20 or a = 15
Now ,
Required two numbers are
1 ) If a = -20 ,
a + 5 = -20 + 5 = -15
2 )If a = 15 ,
a + 5 = 15 + 5 = 20
I hope this helps you.
: )
abhi569:
Sir
Answered by
2
Heya !!!
Let two successive multiple of 5 is ( X) and ( X+5).
According to question,
(X) × ( X+5) = 300
X² +5X = 300
X² +5X -300 = 0
X² +20X -15X -300 = 0
X ( X +20) -15( X +20) = 0
(. X+20) ( X -15) = 0
( X+20) = 0 OR ( X-15) = 0
X = -20 OR X = 15
Hence,
First Number = X = 15
and,
Second number = X +5 = 20
HOPE IT WILL HELP YOU...... :-)
Let two successive multiple of 5 is ( X) and ( X+5).
According to question,
(X) × ( X+5) = 300
X² +5X = 300
X² +5X -300 = 0
X² +20X -15X -300 = 0
X ( X +20) -15( X +20) = 0
(. X+20) ( X -15) = 0
( X+20) = 0 OR ( X-15) = 0
X = -20 OR X = 15
Hence,
First Number = X = 15
and,
Second number = X +5 = 20
HOPE IT WILL HELP YOU...... :-)
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