the product of two successive number is 1980 which one is smaller
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Answered by
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let the numbers be n, (n+1)
according to question
n+(n+1)=1980
n²+n-180=0
solve and find n.
according to question
n+(n+1)=1980
n²+n-180=0
solve and find n.
Answered by
0
The answer is given below :
Let us consider that the numbers are n and n+1, where n belongs to Z.
Then, the product is
= n(n+1)
Given that,
n(n+1) = 1980
=> n² + n - 1980 = 0
=> n² + 45n - 44n - 1980 = 0
=> n(n+45) - 44(n+45) = 0
=> (n+45)(n-44) = 0
So, n = -45 and n = 44
Hence, the numbers are :
-45, -44 or, 44, 45.
The smaller number may be
-45 or, 44.
Thank you for your question.
Let us consider that the numbers are n and n+1, where n belongs to Z.
Then, the product is
= n(n+1)
Given that,
n(n+1) = 1980
=> n² + n - 1980 = 0
=> n² + 45n - 44n - 1980 = 0
=> n(n+45) - 44(n+45) = 0
=> (n+45)(n-44) = 0
So, n = -45 and n = 44
Hence, the numbers are :
-45, -44 or, 44, 45.
The smaller number may be
-45 or, 44.
Thank you for your question.
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