The product of two successive numbers is 1980. The smaller number is
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Let the nos be x and x+1
x(x+1)=1980
x^2+x-1980=0
x^2+45x-44x-1980=0
x(x+45)-44(x+45)=0
(x-44)(x+45)=0
x=44 or x= -45
the nos are x=44
x+1=45
the smallest no. =44
x(x+1)=1980
x^2+x-1980=0
x^2+45x-44x-1980=0
x(x+45)-44(x+45)=0
(x-44)(x+45)=0
x=44 or x= -45
the nos are x=44
x+1=45
the smallest no. =44
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