Question

The product of two successive numbers is 1980. which is the smaller number

Answer 1

let the numbers be n, (n+1)
according to question
$n(n + 1) = 1980 \\ {n}^{2} + n - 180 = 0$
solve and find n

Answer 2

Answer:

The smallest number can be 44 or -45

Step-by-step explanation:

Let the number be x

Since we are given that the another number is successor of the number

So, another number is x+1

Now we are given that The product of two successive numbers is 1980

So, $x(x+1)=1980$

$x^2+x=1980$

$x^2+x-1980=0$

$x^2-44x+45x-1980=0$

$x(x-44)+45(x-44)=0$

$(x-44)(x+45)=0$

Thus the x = 44,-45

Thus the smallest number can be 44 or -45