The product of two successive numbers is 1980. Which is the smaller number? A) 34 b) 44 c) 35 d) 45
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a)is the answer that is benificial
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Let the two successive numbers be x and x + 1
Their product = 1980
To find the numbers, we will multiply x by x + 1
According to the question,
x(x + 1) = 1980
x² + x - 1980 = 0
x² + 45 - 44 - 1980 = 0
x(x + 45) - 44(x + 45) = 0
(x - 44) (x + 45) = 0
x = 44 or x = -45
Any successive number can't be negative.
So, x = 44 or x = 45
The smallest successive number => x
=>
The biggest successive number => x + 1
=> 44 + 1
=>
Their product = 1980
To find the numbers, we will multiply x by x + 1
According to the question,
x(x + 1) = 1980
x² + x - 1980 = 0
x² + 45 - 44 - 1980 = 0
x(x + 45) - 44(x + 45) = 0
(x - 44) (x + 45) = 0
x = 44 or x = -45
Any successive number can't be negative.
So, x = 44 or x = 45
The smallest successive number => x
=>
The biggest successive number => x + 1
=> 44 + 1
=>
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