The product of two successive numbers is 3192. What is the smallest number
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Answered by
6
let the number be=X and (X+1)
according to the sum,
x(x+1) = 3192
x(square) + x -3192=0
x(square) +57x - 56x - 3192 =0
x(x + 57) - 56(x + 57) =0
(x-56)(x + 57) =0
value of x= 56, -57
the required number, that is the smallest number is-56.
according to the sum,
x(x+1) = 3192
x(square) + x -3192=0
x(square) +57x - 56x - 3192 =0
x(x + 57) - 56(x + 57) =0
(x-56)(x + 57) =0
value of x= 56, -57
the required number, that is the smallest number is-56.
supi:
haven't i typed the same ? except for the square, i do not know how to do that..
i'm sorry , you've not seen the answer properly.. this is how , you ought to solve..
Answered by
6
the sum is as follows
let the two numbers be x and x+1
so product is x(x+1)
given x(x+1)= 3192
x²+x-3192=0
x²+57x-56-x-3192=0
x(x+57)-56(x+57)=0
(x-56)(x+57)=0
the numbers are 56 and -57
since it is two positive integers -57 is not valid
so the numbers are 56 and 56+1
let the two numbers be x and x+1
so product is x(x+1)
given x(x+1)= 3192
x²+x-3192=0
x²+57x-56-x-3192=0
x(x+57)-56(x+57)=0
(x-56)(x+57)=0
the numbers are 56 and -57
since it is two positive integers -57 is not valid
so the numbers are 56 and 56+1
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