The product of two successive numbers is 8556. Which is the smallest number?
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Let a and a+1 are the two successive numbers with ‘a’ being the smaller.
Given a × (a + 1) = 8556
⇒ a2 + a – 8556 = 0
This is a quadratic equation in variable a
⇒ a2 + 93a – 92a – 8556 = 0
⇒ a(a+93) – 92(a+93) = 0
⇒ (a – 92) (a + 93) = 0
⇒ a = 92
∴ The smaller number = a = 92
Given a × (a + 1) = 8556
⇒ a2 + a – 8556 = 0
This is a quadratic equation in variable a
⇒ a2 + 93a – 92a – 8556 = 0
⇒ a(a+93) – 92(a+93) = 0
⇒ (a – 92) (a + 93) = 0
⇒ a = 92
∴ The smaller number = a = 92
Answered by
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Answer:
Explanation:
Let x and x+1 are the two successive numbers with ‘x" being the small
Given x × (x + 1) = 8556
⇒ x2 + x – 8556 = 0
This is a quadratic equation in variable x
⇒ x2 + 93x – 92x – 8556 = 0
⇒ x(x+93) – 92(x+93) = 0
⇒ (x – 92) (x + 93) = 0
⇒ x = 92
∴ The smallest number = x = 92
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