Question

The product of two successive numbers is 9506.Which is the smaller of the two numbers?
A) 96
B) 97
C) 98
D) 99

Answer 1

97................................

Answer 2

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Here is your answer.
Let the two successive numbers are x and x+1
ATQ
$x(x + 1) = 9506 \\ x {}^{2} + x = 9506 \\ x {}^{2} + x - 9506 = 0 \\ x { }^{2} + 98x - 97x - 9506 = 0 \\ x(x + 98) - 97(x + 98) = 0 \\ (x + 98)(x - 97) = 0 \\ x + 98 =0 \\ x = - 98 \: \:or \: \\ x - 97 = 0 \\ x = 97$
As number is not in negative
so x = 97
other number is 97+1 = 98
So The smaller of the two numbers is 97

Option (B) 97 is your answer

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