Question

The product of two zeroes of polynomial p(x)=x3-3x2-6x+8 is (-2) find all the zeroes of the polynomial.

Answer 1

Answer:

Step-by-step explanation:

p(x) = 2x³ + 6x² – 4x + 9

Define α,β and γ

Let α,β and γ be the 3 roots

αβ = 3 (Given)

Find the products of all the zeros:

αβγ = - d/a

αβγ = - 9/2

Find the third zeros:

Given αβ = 3

3γ = -9/2

γ = -9/2 ÷ 3

γ = -3/2

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