the product of two zeros of p(x) =x3-5x2-11x+12 is 3 then third zero is
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Answer:
given
p(x) = x³ - 5x² - 11x + 12
let the third root be R
so product of all three roots = 3*R = 3R
now,
we know
product of roots = -constant term/ coefficient of x³
=> 3R = 12
=> R = 12/3 = 4
so , R = 4
thus the third root is 4.
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