Question

The product of (x-3)(x-7)(x+7) is​

Answer 1

Answer:

x³ - 3x² - 49x + 147

Step-by-step explanation:

As per the provided information in the given question, we are asked to calculate the value product of :

$\longmapsto \rm {(x-3)(x-7)(x+7) }$

Step 1 : Rearranging the terms.

$\longmapsto \rm {(x-3) \Big \{(x-7)(x+7) \Big \} }$

Step 2 : Now, simplying in the curly brackets. By using the algebraic identities that is,

• $\bf { (a +b)(a - b) = a^2-b^2}$

$\longmapsto \rm {(x-3) \Big \{ (x)^2 - (7)^2 \Big \} }$

Step 3 : Write the squares of the numbers in the curly brackets.

$\longmapsto \rm {(x-3) \Big \{ x^2 - 49 \Big\} }$

Now, we have to multiply 2 binomials.

Step 4 : Multiply each term of the first binomial with the second binomial.

$\longmapsto \rm {x( x^2 - 49 ) -3(x^2 - 49) }$

Step 4 : Multiply the monomial with each term of the binomial in the brackets.

$\longmapsto \rm {x^3 - 49x -3x^2 +147}$

Step 5 : Rearranging the terms in ascending order.

$\longmapsto \bf {x^3 -3x^2 -49x +147 }$

∴ x³ - 3x² - 49x + 147 is the required answer.

Answer 2

Answer:

(x-3)(x-7)(x+7)

as (a-b)(a+b)= a^2-b^2

therefore, (x-7)(x+7)=x^2-7^2

=x^2-49

so, (x-3)(x^2-49)

= x^3 - 49x - 3x^2 + 147

=x^3 - 3x^2 - 49x + 147