Question

the product of zero of x^2-3x+(k-1) is 7 then find k​

Answer 1

Answer:

Step-by-step explanation:

Let the zeroes be x and y

xy=-c/a

7=-(k-1)

7=-k+1

7-1=-k

6=-k

-6=k

So k=-6

Answer 2

Answer:

$k = 8$

Step-by-step explanation:

Compare x²-3x+(k-1) with ax²+bx+c ,we get

a =1 , b = -3 , c = (k-1)

$Product\: of \: zeroes =7\:(given)$

$\implies \frac{c}{a}=7$

$\implies \frac{k-1}{1}=7$

$\implies k-1 = 7$

$\implies k= 7+1$

$\implies k = 8$

Therefore,

$k = 8$

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