The product of zeroes of 2x²-3x+6
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2
Answer:
2x² + 3x - 6
Roots = α and β
So as in a quadratic Polynomial :-
-b/a = Sum of roots = α + β
c/a = Product of roots = αβ
Now in our polynomial
a = 2
b = 3
c = -6
So
Sum of roots = -3/2
Product of roots = -6/2 = -3
Now we have to find out the value of
α² + β²
Now as we know
a² + b² = (a + b)² - 2ab
So
α² + β² = ( α + β)² - 2 (αβ)
= (-3/2)² - 2(-3)
= 9/4 + 6
= (9 + 24)/4
= 33/4
So α² + β²
\Huge{\boxed{\sf{= \dfrac{33}{4}}}}
=
4
33
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Answered by
2
8
Step-by-step explanation:
product of zeros is the product of coefficient of x² term and constant term
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