Question

The product of zeroes of polynomial p(x) = x2-81 is
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Answer 1

To get the zeroes of any polynomial just put it equal to 0.

So, here p(x) = 0

=> x^2 -81 = 0

=> x^2 = 81

=> x = ±9

Thus, zeroes of the polynomial are 9 and -9.

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Answer 2

Answer:

There is a formula to find the product of zeros

that is

product of zeros of polynomial = constant term/ coefficient of x^2

= 81/1

= 81

Additional information

Some more formula

formula for linear polynomial

sum of zeros = - constant term / coefficient of X

formula for quadractic equation

Sum of zeros= coefficient of x/ coefficient of x^2

formula for cubic polynomial

Product of zero = (-constant term)/ coefficient of x^2