Question

the product of zeroes of the polynomial 5x+3x^2+7​

Answer 1

Step-by-step explanation:

3x^2+5x+7=0

x=-5+_√5^2-4(3)(7)/2(3)

=-5+_√25-84/6

=-5+_√-59/6

=-5+_√9.83

=-5+_3.13

x=-5+3.13 ; -5-3.13

=-1.87 ; -8.13

these are the zeros

product of zeros

1.87×-8.13

=-15.2031

tq

märk mē ãß bræñlïéßt

Answer 2

Answer:

7/3

Note:

If A and B are the zeros of a given quadratic polynomial ax² + bx + c , then ;

Sum of zeros , (A+B) = -b/a

Product of zeros , (A•B) = c/a

Solution:

Here,

The given quadratic polynomial is :

5x + 3x² + 7 .

The given quadratic polynomial can be rewritten as ; 3x² + 5x + 7 .

Clearly,

We have ;

a = 3

b = 5

c = 7

Also,

The product of zeros of the given quadratic polynomial will be given as c/a.

Thus,

Product of zeros = c/a = 7/3

Hence,

The required answer is 7/3 .