Question

the product of zeroes of x^3+4x^2+2x-8 is please help me don't write wrong answer if you don't know not answer
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Answer 1

Answer:

Product of zeroes of a cubic polynomial is given by :

$\alpha \beta \gamma = - \: d \div a$

Now ,

d = –8

Hence , –d = 8

Also , a = 1

Hence , product of zeroes = 8 / 1 = 8