Question

the product of zeros of quadratic polynomial 2x^2-8x-3is​

Answer 1

Answer:

α × β = $\frac{c}{a}$

HERE, A = +2

AND, C = -3

→ $\frac{c}{a} = \frac{2}{-3} = \frac{-2}{3}$

Answer 2

Answer:

-3/2

Step-by-step explanation:

We know that if ax² + bx + c is a quadratic equation, then product of the zeroes is given by c/a

Here, ax² + bx + c is represented by 2x²-8x-3

So, on comparing both of them, a = 2, b = -8, c = -3

So, Product of zeroes  = c/a = -3/2

❖ Extra information:

⟡ Sum of zeroes

=> In this equation  ax² + bx + c, Product of zeroes is given by -b/a

Hope it helps!