Question

the product of zeros of the polynomial f(x)=ax'3-6x'2+11x-6 is 4 then the value of a​

Answer 1

Answer:

the value of a is 3/2.

Step-by-step explanation:

If αβγ= -d/a = 4

then,

4 = -(-6)/a

4 = 6/a

=> a = 6/4

=> a = 3/2

Hence, the value of a is 3/2.

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i hope it will helps you friend

Answer 2

Answer:

Given, f(x) = ax^3 - 6x^2 + 11x -- 6

Product of zeroes == 4

We know,

Product of zeroes = - d/a

Putting values

4 = - (-6)/a

4 = 6/a

a = 6/4

a = 3/2 (Answer)