Question

the product P of three positive integer is 9 times their sum and one of the integer is sum of other two sum of possible vales of p is​

Answer 1

Step-by-step explanation:

Let x, y, z be three positive integers.

According to statement

x*y*z=9*(x+y+z).........(1)

Second condition

one integer is sum of other two,

so let x=y+z.........(2)

Put (2) in (1), then,

x*y*z = 9(x + x) = 18x

=>y*z=18

possible values of y and z are

Case 1. y=1, z=18; => x=19

Case 2. y=2, z=9; => x=11

Case 3. y=3, z=6; => x=9

sum of possible values of p are

1 × 18 × 19 = 342

2 × 9 × 11 = 198

3 × 6 × 9 = 162

So sum = 602

Answer 2

Answer:

sum of 602...................