The production of oil (in lakh tonnes) in five refineries in India during 1992 is given below:
Construct a bar graph to represent the above data so that the bars are drawn horizontally.
give ans.
Answers
Answer:
Right circular cone of height = 8.4 cm . Radius of its base =2.1 cm .
It is melted and recast into sphere. As we know that,
Volume of a cone =1/3 pi r^ 2 h .
Volume of sphere =4/3 Pi r^ 3
Using this formula in the equation, we get.
Volume of ne = Volume of sphere.
→ 1/3 * pi * R ^ 2 * h = 4/3 * pi * r ^ 3 .
Rightarrow Pi R^ 2 h=4 pi r^ 3 .
Rightarrow R^ 2 h=4r^ 3
Rightarrow(2.1)^ 2 *8.4=4* r^ 3 .
Rightarrow4.41*8.4=4* r^ 3
37.044 = 4r ^ 3 Rightarrow3
r ^ 3 = 9.261 .
r ^ 3 = (2.1) ^ 3 .
>r=2.1 cm .
Step-by-step explanation:
Right circular cone of height = 8.4 cm . Radius of its base =2.1 cm .
It is melted and recast into sphere. As we know that,
Volume of a cone =1/3 pi r^ 2 h .
Volume of sphere =4/3 Pi r^ 3
Using this formula in the equation, we get.
Volume of ne = Volume of sphere.
→ 1/3 * pi * R ^ 2 * h = 4/3 * pi * r ^ 3 .
Rightarrow Pi R^ 2 h=4 pi r^ 3 .
Rightarrow R^ 2 h=4r^ 3
Rightarrow(2.1)^ 2 *8.4=4* r^ 3 .
Rightarrow4.41*8.4=4* r^ 3
37.044 = 4r ^ 3 Rightarrow3
r ^ 3 = 9.261 .
r ^ 3 = (2.1) ^ 3 .
>r=2.1 cm .