Question

The products for the following reactions are
Br
(i) CH3 -C-CH2– CH3 + alc. KOH —— X
H
(ii) CHA CHA CHA CH2
→ Y + Z
CH3
(a) X = (CH3)2C = CH2, Y = CH3CH2CHO, Z = CH3 CH2 CHO
(b) X= CH = CH2, Y = CH2CHO, Z= CH2COOH
(c) X = CH3 - CH = CH –
CH – CH3
CH3
Y = CH2 CH2 CH2,4 = HCHO
(d) X = CH - CH = C(CH3)2, Y = HCHO, Z = CH2 CHO​

Answer 1

Explanation:

X=CH

3

−CH=

CH

3

∣

C

−CH

3

,Y=CH

3

CHO,Z=CH

3

COCH

3

Compound B gives positive Fehling's test. It shows that it is an aldehyde and gives iodoform test which shows it has COCH

3

group. Compounds C is a ketone because it does not give Fehling's test but gives iodoform test which shows its also has COCH

3

group