The profit earned by a vendor by selling bananas at a gain of 10% is ₹30 more than when he sells it a loss of 10% . Find the C.P. of bananas.
Answers
Given :-
The profit earned by a vendor by selling bananas at a gain of 10% is ₹30 more than when he sells it a loss of 10% .
To find :-
The Cost Price of bananas .
Solution :-
Let the Cost Price of bananas be Rs. X
Profit on them = 10%
We know that
Selling Price = [(100+g)/100]×CP
=> SP = [(100+10)/100]×X
=> SP = (110/100)×X
=> SP = (11/10)×X
=> SP = Rs. 11X/10
and
Loss on it = 10%
We know that
Selling Price = [(100-l)/100]×CP
Selling Price = [(100-10)/100]×X
=> SP = (90/100)×X
=> SP = (9/10)×X
=> SP = Rs. 9X/10
Given that
SP at gain = SP at loss + Rs. 30
=> 11X/10 = (9X/10)+30
=> (11X/10)-(9X/10) = 30
=> (11X-9X)/10 = 30
=> 2X/10 = 30
=> X/5 = 30
=> X = 30×5
=> X = 150
Therefore, X = Rs. 150
Answer:-
The Cost Price of bananas is Rs. 150
Check :-
The CP of bananas = Rs. 150
Gain on them = 10%
We know that
SP = [(100+g)/100]×CP
=> SP = (110/100)×150
=> SP = 11×15 = Rs. 165
Loss on them = 10%
We know that
SP = [(100-l)/100]×CP
=> SP = (90/100)×150
=> SP = 9×15 = Rs. 135
The difference between two SPs
= 165-135
= Rs.30
Verified the given relations in the given problem.
Used formulae:-
♦ SP = [(100+g)/100]×CP
♦ SP = [(100-l)/100]×CP
g = gain
l = loss
SP = Selling Price
CP = Cost Price
Answer:
CP of bananas= 150
Step-by-step explanation:
Let the CP of bananas be b
When the vendors sells at 10% gain,
SP (at 10%gain)=(1+10/100)x= 1.1x
SP (at 10%loss)=(1+10/100)x=0.9x
according to the question
1.1x-0.9x=30
0.2x=30
x=30/0.2
x=150