The projection length of a variable vector
xi + yj + zk on the vector
P = i + 29 + 3k is 6. Let l be the
minimum projection length of the vector
->
22 î + y2ģ+ z2k on the vector P, then
the value of 3 12 + 152 is
Answers
Answer:
Step-by-step explanation:
r
=x
i
^
+y
j
^
+z
k
^
u
=
i
^
+
j
^
+
k
^
r
⋅
u
=10
(x
i
^
+y
j
^
+z
k
^
)⋅(
i
^
+
j
^
+
k
^
)=10
x+y+z=10
HERE x,y,z are natural number So x,y,z cannot be negative and zero as well
so atleast x,y,z should be 1
so values of x,y,z vary from 2 to 8
So combination of values becomes (
3
7
)+1
possible values=
4!3!
7!
+1
possible values=
3×2×1
7×6×5
+1
possible values=35+1
possible values=36
Step-by-step explanation:
ANSWER
r
=x
i
^
+y
j
^
+z
k
^
u
=
i
^
+
j
^
+
k
^
r
⋅
u
=10
(x
i
^
+y
j
^
+z
k
^
)⋅(
i
^
+
j
^
+
k
^
)=10
x+y+z=10
HERE x,y,z are natural number So x,y,z cannot be negative and zero as well
so atleast x,y,z should be 1
so values of x,y,z vary from 2 to 8
So combination of values becomes (
3
7
)+1
possible values=
4!3!
7!
+1
possible values=
3×2×1
7×6×5
+1
possible values=35+1
possible values=36