Physics, asked by shadnan7862, 10 months ago

The propelling force of a rocket increases uniformly from zero to N in the first
12 m and remains constant for the next 40 m. Find the total work done​

Answers

Answered by MOSFET01
5

Question:

The propelling force of a rocket increases uniformly from zero to 1 N in the first in the first 12 m and remains constant for the next 40 m. Find the total work done.

Answer:

Force \propto Height

F \propto h

F = p.h

F = Force

h = height

p = constant

p = \dfrac{F}{h}

p = \dfrac{1}{12}

For first 12 m Force is increased from 0 to 1 N (as you have not given i am considering according to it)

W_{1} = \int F dx

W_{1} = \int p.h dx

W_{1} = p \int h dx -- {p is constant}

W_{1} = \dfrac{1}{12}\times\Big[\dfrac{h^{2}}{2}\Big]_{0}^{12}

W_{1} = \dfrac{1}{12}\times\dfrac{12^{2}}{2}

W_{1} = 6 Joule

W_{2} = F × h_{2}

W_{2} = 1 × 40

W_{2} = 40 Joule

W_{1}\: + \: W_{2} = 40 + 6 = 46 Joules

Answer is 46 Joules

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