Science, asked by dhimankavita55, 9 months ago

The properties of compound are similar to thoseof their constituent elements (true ya false)​

Answers

Answered by Mysterioushine
3

Answer :

\huge{\boxed{\purple{\sf{False}}}}

Explanation :

Compounds are formed by the chemical combination of constituent elements in a fixed ratio. Due to this reason elments have only one kind of atom where as compound has two or more than two kinds of atoms.Elements cannot be broke down into simpler substances , where as Compounds can be broke down into simpler substances.

Hence , The Properties of Compound are not similar to those of properties of elements.

Answered by abdulrubfaheemi
0

Given :

The velocity with which the object is thrown in vertical upward direction is 'u'

To find :

The Maximum height attained by the object

Solution :

When a body/object is thrown vertically upwards the velocity(final velocity) at highest point will be zero.

And the acceleration experienced by the object/body is nothing but the acceleration due to gravity which is equal to -g. (Negative sign indicates that the acceleration is opposite direction of motion)

Initial velocity of the object/body is the velocity with which it is thrown . So , In this case initial velocity of the object will be 'u'.

Now we have ,

u = u

v = 0

a = -g

s = h (height attained in this case)

From Second equation of motion ,

\star \: { \boxed{ \sf{ \purple{v {}^{2} - u {}^{2} = 2as }}}}⋆

v

2

−u

2

=2as

Where ,

v is Final velocity

u is initial velocity

a is acceleration

s is height attained (in this case)

Substituting the values we have ,

\begin{gathered}: \implies \sf \: (0) {}^{2} - (u) {}^{2} = 2( - g)(h) \\ \\ : \implies \sf \: 0 - u {}^{2} = - 2gh \\ \\ : \implies \sf \: - u {}^{2} = - 2gh \\ \\ : \implies \sf \not{ - }u {}^{2} = \not{ - }2gh \\ \\ : \implies \sf \: {u}^{2} = 2gh \\ \\ : \implies {\boxed{ \sf {\pink {\: h = \frac{ {u}^{2} }{2g} }}}}\end{gathered}

:⟹(0)

2

−(u)

2

=2(−g)(h)

:⟹0−u

2

=−2gh

:⟹−u

2

=−2gh

:⟹

−u

2

=

−2gh

:⟹u

2

=2gh

:⟹

h=

2g

u

2

Hence , The Maximum height attained by the object is \sf{\dfrac{u^2}{2g}}

2g

u

2

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