Math, asked by pratyushdash1999, 1 month ago

The proportion of 2 numbers is 10:1 and their sum is 1188. What is the number?​

Answers

Answered by kirangupta11j
0

Answer:

Let the numbers be 11x,12x then their sum =11x+12x=460

⇒23x=460

∴x=

23

460

=20

∴ the numbers are 11x=11×20=220 and 12x=12×20=240

Step-by-step explanation:

i like to help~♥~~♥~~♥~~♥~~♥~

Answered by Tulsi4890
0

The two numbers x and y are 1080 and 108 respectively.

Given:

Two numbers proportion is 10:1 and sum is 1188.

To Find:

The value of two numbers.

Solution:

We are required to find the value of the two numbers whose sum is 1188.

Let the two numbers be x and y and the proportion of the two numbers be 10:1.

x+y = 1188 -----(1)

x:y = 10:1

x/y = 10/1

x = 10y --------(2)

x = 10y    substitute in equation(1),

we get the value of y

10y+y = 1188

11y = 1188

y = 108   substitute in equation(2),

we get the value of x

x = 10×108

  = 1080

Therefore, The two numbers x and y are 1080 and 108 respectively.

#SPJ2

Similar questions