The proportion of copper, carbon and oxygen in the copper carbonate are.......by weight. *
1) 3:4:2
2) 3:4:1
3) 5:4:2
4) 5:4:1
please answer option no.
Answers
Answered by
0
Solution:- (A) 0.56
CuCO
3
+2HCl→CuCl
2
+CO
2
+H
2
O
Molecular weight of CuCO
3
=123.5g
No. of moles in 3.7g of CuCO
3
=
123.5
3.7
=0.03 mol
Also,
2moldm
−3
HCl, i.e.,
No. of moles HCl in 1dm
3
volume =2
No. of moles of HCl in 25cm
3
=
1000
25
×2=0.05 mol
Here HCl is limiting reagent.
Therefore, from the above reaction,
Volume of gas produced when 2 moles of HCl reacts =22.4dm
3
Volume of gas produced when 0.05 moles of HCl reacts =
2
22.4
×0.05=0.56dm
Answered by
2
Answer:
option 3 is correct answer Mark as brainliest Plz
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