Question

The proposed length of the cannon was 220m. If launch velocity is 11kmps, what would have been the unrealistically large acceleration during launch?

Answer 1

Answer and Explanation:

Given data

Length of the proposed large canon

L

=

220

m

Required Speed of the space capsule launched from the canon

v

=

10.97

k

m

=

1.097

×

10

4

m

Acceleration due to gravity

g

=

9.80

m

/

s

2

Part a)

Let a be the required acceleration in the canon barrel.

Then the required speed can be expressed as

v

=

√

2

a

L

Therefore required acceleration of the space capsule in the canon barrel

a

=

v

2

2

L

a

=

(

1.097

×

10

4

)

2

2

×

220

a

=

2.735

×

10

5

m

/

s

2

Part b)

The ratio of space capsule acceleration to free fall acceleration

a

g

=

2.735

×

10

5

9.80

a

g

=

27908.4

This force is 27908.4 times stronger than the gravitational force.