Question

The protons are accelerated by a cyclotron, when a
magnetic field of 2.0 T is applied perpendicular to
the plane of the dees. Calculate the energy of the
proton in MeV, if the circular path of the protons
has a radius of 40 cm before the protons leave the
cyclotron. Given mass of a proton = 1.67 x 10 kg.
​

Answer 1

Answer:

Given, Magnetic field B=2T

Potential gap ΔV=100kV

We know that, r=

qB

mv

⇒V=100×10

3

=10

5

volts

So, KE gained in each revolution =e(V)+e(V)=2e(V)=2e×10

5

Thus, number of revolution N=

2×10

5

20×10

6

=100revolution