Chemistry, asked by johndar239, 6 hours ago

The Pt concentration obtained was: Pt = 1850.0 ppm (mg/kg). 40 g of this catalyst is then leached for 3 hours at 90oC with 300 mL of a 6.0 M hydrochloric acid (HCl) solution, and 150 ml of a 5.0% weight percentage sodium hypochlorite (NaOCl) solution together as leaching agent. The solution is then made-up with deionized water to 500 ml and a representative sample of this was then analysed by ICP-OES in the liquid state. The following concentration for Pt were given: Pt = 322.4 ppm (mg/L). Calculate the percentage recovery of the Pt in solution.​

Answers

Answered by sankushreya
0

Explanation:

The Pt concentration obtained was: Pt = 1850.0 ppm (mg/kg). 40 g of this catalyst is then leached for 3 hours at 90oC with 300 mL of a 6.0 M hydrochloric acid (HCl) solution, and 150 ml of a 5.0% weight percentage sodium hypochlorite (NaOCl) solution together as leaching agent. The solution is then made-up with deionized water to 500 ml and a representative sample of this was then analysed by ICP-OES in the liquid state. The following concentration for Pt were given: Pt = 322.4 ppm (mg/L). Calculate the percentage recovery of the Pt in solution.are

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