Question

the pth, qth and rth terms of an ap are a,b and c respectively. show that a(q-r)+b(r-p)+c(p-q)=0​

Answer 1

Answer:

f+(p-1)d=a

p=(a-f)/d+1

f+(q-1)d=b

q=(b-f)/d+1

f+(r-1)d=c

r=(c-f)/d+1

a(q-r)=a{(b-c)/d

Similarly calculate b(r-p) and c(p-q)

Then add them

you will get 0