The pth term of an AP is (3p – 1)/6. The sum of the first n terms of the AP is
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Step-by-step explanation:
Given :-
- AP is (3p – 1)/6.
To Find :-
- What is ap
Solution :-
we know the formula :-
Sn=(n/2) [a(1)+a(n)]
- Putting value
=> a(n)=(3-1)/6
=> S(n)=(n/2) [(1/2)+(3n-1)/6]
=> (n/2) [(3+3n-1)/6]
=> (n/2) (3n+2)/6
=> 3n^2+2n/12
=. n/12(3n+1)
Answer is n/12(3n+1)
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5
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answer for the given problem is given
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