Math, asked by anjaliksbgm, 3 months ago

the pth term of an AP is q and the qth term is p, prove that its nth term is (p + q --n).​

Answers

Answered by tanmaydebnath34
0

Step-by-step explanation:

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I once was a man with dignity and grace

Now I'm slippin' through the cracks of your cold embrace

So please, please

Could you find a way to let me down slowly?

A little sympathy, I hope you can show me

If you wanna go then I'll be so lonely

If you're leavin', baby, let me down slowly

Let me down, down, let me down, down, let me down

Let me down, down, let me down, down, let me down

If you wanna go then I'll be so lonely

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And I can't stop myself from fallin' (down) down

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Answered by Anonymous
1

As we know the Pth term of an AP is Q.

  • → Tₚ = q
  • → a + (p - 1)d = q ...[1]

Qth term of an AP is P.

  • → Tq = p
  • → a + (q - 1)d = p ...[2]

Now, If we will Equalise both the EQUATIONS so we'll found that;

→ (p -1)d – (q - 1)d = (q - p)

→ pd - d - qd + d = (q - p)

→ pd - qd = (q - p)

→ -d(q - p) = (q - p)

→ -d = 1

→ d = –1

We're going to find the FIRST TERM of an AP using the value of common Difference.

→ a + (p - 1)d = q

→ a - (p - 1) = q

→ a = q + (p - 1)

a = (q + p - 1)

Finally, It's time to PROVE that nth term will be (p + q - n).

→ Tₙ = a + (n - 1)d

→ Tₙ = (q + p - 1) + (n - 1)(-1)

→ Tₙ = (q + p - 1) - (n - 1)

→ Tₙ = q + p - 1 - n + 1

Tₙ = (q + p - n)

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