Physics, asked by komal116, 1 year ago

the PV graph for a monatomic gas is shown in figure find the energy absorbed by the gas during this process

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Answered by aqibkincsem

As the process opted here is a cyclic process, W = Q because the heat energy transferred is equal to the W.

The total work that has been done in this process is equal to the area of the cyclic process.

Hence W = ½ x (2V0-V0) (3P0-2P0)

= ½ V0P0.

Answered by Anonymous

Explanation:

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As the process opted here is a cyclic process,

W = Q because the heat energy transferred is equal to the W.

The total work that has been done in this process is equal to the area of the cyclic process.

Hence

W = ½ x (2V0-V0) (3P0-2P0)

= ½ V0P0.

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