Question

the Pythagora triplet whose one number is 16 and other​

Answer 1

2m=16

m=16\2

= 8.

m^2=8.

so,8^2=64.

now using the formula

m^2 - 1

since m^2 is 8

8^2-1

64 - 1=

63.

m^2 + 1

64 + 1 =

65.

Therefore, the Pythagorean triplets are 16,63,65.