The Pythagorean triple whose smallest number is 30
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Step-by-step explanation:
Solution:
General form of pythagorean triplets are m
2
−1,2m,m
2
+1
⇒First member of triplet a=2m=30⇒m=15
Since, it is even
⇒So, second member of triplet b=(m)
2
−1=15
2
−1=225−1=224
⇒And third member of triplet c=m
2
+1=225+1=226
Hence, A is the correct option.
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